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x^2+0.38x-0.35=0
a = 1; b = 0.38; c = -0.35;
Δ = b2-4ac
Δ = 0.382-4·1·(-0.35)
Δ = 1.5444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.38)-\sqrt{1.5444}}{2*1}=\frac{-0.38-\sqrt{1.5444}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.38)+\sqrt{1.5444}}{2*1}=\frac{-0.38+\sqrt{1.5444}}{2} $
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